Asked by Sandhya
A solution is made by mixing 5.00 × 102 mL of 0.167 M NaOH with 5.00 × 102 mL of 0.100 M CH3COOH. Calculate the equilibrium concentrations of H+, CH3COOH, CH3COO−, OH−, and Na+.
Answers
Answered by
DrBob222
NaOH + HOOCCH3 ==> NaOOCCH3 + H2O
millimols CH3COOH = mL x M = ?
millimols NaOH = mL x M = ?
Can you take it from here. If not please explain in detail what you don't undrstand.
millimols CH3COOH = mL x M = ?
millimols NaOH = mL x M = ?
Can you take it from here. If not please explain in detail what you don't undrstand.
Answered by
Sandhya
Yes I can thank you so much Dr. Bob! I got an answer of 8.38 as a pH which seems to be right. Thanks again!
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