Asked by sarah

What is the empirical formula of the compound with a mass percent composition of 70.0% Fe and 30.0% O? (Type your answer using the format CH4 for CH4
Answered by Engineer
Fe2O3
Answered by DrBob222
Take a 100 g sample which gives you
70.0 g Fe and 30.0 g O.
mols Fe = 70.0/55.85 = about 1.25
mols O = 30.0/16 = 1.875

Find the ratio; the easy way to do that is to divide the smaller number by itself and do that to the other number too.
1.25/1.25 = 1
1.875/1.25 = 1.5
This obviously 2:3 so the formula is
Fe2O3.
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