Asked by helpless

You are a thief and you want to lower yourself from the rooftop to a second floor window, which is at a distance H=12m below the tip of the roof. You want to use a nylon rope, which has a failure stress of 400 MPa, and a Young’s modulus of 1 GPa. If you weigh 225 lb, what diameter rope, Dmin, should you choose if you want a safety factor of 2 against failure?
Answered by sat
2.4
10
Answered by Mat
Thanks Sat, but can you write your reasoning behind the answer?
Answered by Mag
Rotating blade (body force in axial loading)

A blade is fixed to a rigid rotor of radius R spinning at omega rad/sec around the vertical z-axis (see figure). Neglect the effects of gravity.

Calculate the peak stress in the blade: sigma_max_n
Calculate the blade elongation: delta
Calculate the displacement of the blade mid-section: u_x(L/2)

sigma max n =
delta =
u_x(L/2) =
Answered by mehwish
please help me what is the solution of above questions.?
Answered by mehwish
please help me if anybody find the solution of above question.
Answered by Flaminuous
Has somebody figured out?
Answered by My
Anybody for Problem 1 and 2?
Answered by Neon
Problem 1 and 2?
Answered by rka
help me plz
Answered by Nart
Problem 1 and 2 please?
Answered by gluglu
rho*omega^2*(R*L+L^2/2)
(rho*omega^2/E)*(L^3/3+L^2*R/2)
(rho*omega^2/E)*(11*L^3/48+3*L^2*R/8)
Answered by FLu
Thanks gluglu, anyone for last problem in question 1?
Answered by Magnum
Anyone for last question in Problem 1 please?
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