9-x=3/2y as a slope intercept form

Answer 1

To convert the equation 9-x=3/2y to slope-intercept form, we need to solve for y.

Starting with the given equation:
9 - x = 3/2y

To solve for y, we can isolate y on one side of the equation:

1. Add x to both sides:
9 - x + x = 3/2y + x
9 = 3/2y + x

2. Subtract x from both sides:
9 - x = 3/2y
Now we have the equation in the form y = mx + b, where m is the slope and b is the y-intercept.

3. Divide by 3/2 to solve for y:
y = (9 - x) / (3/2)
y = (9 - x) * (2/3)
y = 18/3 - 2x/3
y = 6 - 2x/3

Therefore, the equation 9-x=3/2y in slope-intercept form is:
y = -2/3x + 6

Answer 2

y = -2/3x + 6 x y axis form

Answer 3

To convert the equation y = -2/3x + 6 to x-y axis form, we need to rearrange the equation to isolate x.

Starting with the equation:
y = -2/3x + 6

First, let's add 2/3x to both sides to isolate the term involving x:
y + 2/3x = 6

Now, we need to rewrite the equation in the form x = m*y + b, where m is the slope and b is the x-intercept. To isolate x, we need to solve for x:

2/3x = 6 - y
x = (6 - y) * 3/2
x = 18/2 - 3/2*y
x = 9 - 3/2y

Therefore, the equation y = -2/3x + 6 in x-y axis form is:
x = 9 - 3/2y

Answer 4

(1, -7) (0, 10) Id this the correct graph of 3X-y=10? And why?

Answer 5

To determine if the points (1, -7) and (0, 10) lie on the graph of the equation 3x - y = 10, we can substitute the x and y values from each point into the equation.

For the point (1, -7):
3(1) - (-7) = 10
3 + 7 = 10
10 = 10

For the point (0, 10):
3(0) - 10 = 10
0 - 10 = 10
-10 = 10

As we can see, the point (1, -7) satisfies the equation 3x - y = 10, but the point (0, 10) does not satisfy the equation. Therefore, the correct graph of the equation 3x - y = 10 would go through the point (1, -7) but not through the point (0, 10).