Question

What is the slope-intercept form of the linear equation 2x + 3y = 6?


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Answer 1

put it all in order

Answer 2

To convert the linear equation \(2x + 3y = 6\) into slope-intercept form, we need to solve for \(y\).

1. Start with the original equation:
\[
2x + 3y = 6
\]

2. Isolate \(3y\) by subtracting \(2x\) from both sides:
\[
3y = -2x + 6
\]

3. Now, divide everything by \(3\) to solve for \(y\):
\[
y = -\frac{2}{3}x + 2
\]

Now that we have \(y\) in terms of \(x\), the slope-intercept form of the equation is:
\[
y = mx + b
\]
where \(m\) is the slope and \(b\) is the y-intercept.

From the equation \(y = -\frac{2}{3}x + 2\):
- The slope \(m = -\frac{2}{3}\)
- The y-intercept \(b = 2\)

If you need to fill in specific boxes based on your question format, they may need to be filled out as follows:

- Slope (m): \(-\frac{2}{3}\)
- y-intercept (b): \(2\)

Please confirm if you need further assistance!

Answer 3

Sure! The slope-intercept form of the linear equation \(2x + 3y = 6\) is:

\[
y = -\frac{2}{3}x + 2
\]

In order:

1. **Slope (m)**: \(-\frac{2}{3}\)
2. **Y-intercept (b)**: \(2\)

If you're putting these in specific boxes, they would be:

- **Slope (m)**: \(-\frac{2}{3}\)
- **Y-intercept (b)**: \(2\)

Let me know if you need further assistance!