Asked by Shadow
How much water must be added to 6 mL of a 0.05M stock solution to diltue it to 0.02M ?
The answerI got is 15 mL. Is this correct? Thanks
The answerI got is 15 mL. Is this correct? Thanks
Answers
Answered by
DrBob222
Close but no cigar.
6 mL x 0.05 = xmL*0.02
x mL = 15.0 mL which is the final volume. Therefore, you must add 9 mL to the 6 to make 15.0. Technically, you want the final volume to be 15.0 mL; the amount you add may NOT be EXACTLY 9.0 mL since volumes are not additive.
6 mL x 0.05 = xmL*0.02
x mL = 15.0 mL which is the final volume. Therefore, you must add 9 mL to the 6 to make 15.0. Technically, you want the final volume to be 15.0 mL; the amount you add may NOT be EXACTLY 9.0 mL since volumes are not additive.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.