Question
A newly discovered element, Mysternium (Atomic symbol My) has two isotopes and an average atomic mass of 296.7286 amu. One of the isotopes, My-296 has a natural abundance of 61.528% and has a mass value of 295.9064 amu. What is the mass of the second isotope?
Answers
The one isotope is 61.528%; the other one is 100-61.528.
(0.61528*295.9064)+ (0.38472*x) = 296.7286
Solve for x.
(0.61528*295.9064)+ (0.38472*x) = 296.7286
Solve for x.
Thank you. I was so confused on what to do.
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