Ask a New Question

Asked by Katherine

What mass of precipitate will form if 1.50L of concentrated Pb(ClO3)2 is mixed with 0.200L of 0.280M of NaI? Assume the reaction is complete
12 years ago

Answers

Answered by DrBob222
You must assume there is enough Pb(ClO3)2 to use all of the NaI.
Pb(ClO3)2 + 2NaI ==> PbI2 + 2NaClO3
mols NaI = M x L = ?
Convert mols NaI to mols PbI2 using the coefficients in the balanced equation.
Convert mols PbI2 to g. g = mols x molar mass.
12 years ago

Related Questions

what precipitate (if any) will form? Al(NO3)3 (aq) + Ba(OH)2 (aq) the mass of CuSCN precipitate is 1.379g, what is the mass of copper in the precipitate? What mass of precipitate will form if 1.50 L of concentrated Pb(ClO3)2 is mixed with 0.750 L of 0.29... What mass of precipitate is formed when 0.50 L of 2.50 mol/L aqueous CaCl2 with 1100 mL of 3.50 mol/... what mass of precipitate will form if 1.5L of concentrated pb(clo3)2 is mixed with .55L of.190 M NaI What mass of precipitate is formed when 0.750 L of 2.50 mol/L CaCl2 reacts with 650 mL of 1.75 mol/L... what mass of precipitate will form if a saturated solution of potassium nitrate is dropped from a te... What mass of precipitate will be formed when 25 mL of 0.532 M silver nitrate is mixed with 25 mL of... What mass of precipitate is produced when 40.0 mL 0.100M lead nitrate reacts with 30.0 mL 0.100M al...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use