Asked by Katherine
What mass of precipitate will form if 1.50L of concentrated Pb(ClO3)2 is mixed with 0.200L of 0.280M of NaI? Assume the reaction is complete
Answers
Answered by
DrBob222
You must assume there is enough Pb(ClO3)2 to use all of the NaI.
Pb(ClO3)2 + 2NaI ==> PbI2 + 2NaClO3
mols NaI = M x L = ?
Convert mols NaI to mols PbI2 using the coefficients in the balanced equation.
Convert mols PbI2 to g. g = mols x molar mass.
Pb(ClO3)2 + 2NaI ==> PbI2 + 2NaClO3
mols NaI = M x L = ?
Convert mols NaI to mols PbI2 using the coefficients in the balanced equation.
Convert mols PbI2 to g. g = mols x molar mass.
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