Asked by N
What mass of precipitate will be formed when 25 mL of 0.532 M silver nitrate is mixed with 25 mL of 0.333 M NaCl?
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Answered by
DrBob222
This is a limiting reagent problem. You know that because amounts are given for BOTH reactants.
AgNO3 + NaCl ==> AgCl + NaNO3
mols AgNO3 = M x L = approx 0.013 but need that more accurately.
mols NaCl = M x L = ? approx 0.0083
So the amount of AgCl that can be formed from the AgNO3 is 0.01 something and that from the NaCl is 0.008 something. The correct answer is ALWAYS the smaller number.
Use the smaller number and convert to grams AgCl. g AgCl = mols AgCl x molar mass AgCl.
AgNO3 + NaCl ==> AgCl + NaNO3
mols AgNO3 = M x L = approx 0.013 but need that more accurately.
mols NaCl = M x L = ? approx 0.0083
So the amount of AgCl that can be formed from the AgNO3 is 0.01 something and that from the NaCl is 0.008 something. The correct answer is ALWAYS the smaller number.
Use the smaller number and convert to grams AgCl. g AgCl = mols AgCl x molar mass AgCl.
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