The number of moles of KMnO4 required to react with 5 moles of H2O2 in acidic medium is ?

2(8H+ + MnO4- + 5e- --> Mn2+ + 4H2O)

5(H2O2 --> O2 + 2H+ + 2e-)
--------------------------------------…
16H+ + 2MnO4- + 5H2O2 --> 2Mn2+ + 5O2 + 8H2O + 10H+

2 moles

To determine the number of moles of KMnO4 required to react with 5 moles of H2O2 in acidic medium, you need to use the balanced chemical equation for the reaction between KMnO4 and H2O2 in an acidic solution.

The balanced chemical equation for this reaction is:

2 KMnO4 + 3 H2O2 + 2 H2SO4 --> 2 MnSO4 + 3 O2 + K2SO4 + 4 H2O

This equation tells you that it takes 2 moles of KMnO4 to react with 3 moles of H2O2 in the presence of 2 moles of H2SO4.

Now, you can set up a simple proportion to find out the number of moles of KMnO4 required:

2 moles of KMnO4 / 3 moles of H2O2 = x moles of KMnO4 / 5 moles of H2O2

Cross-multiplying, you get:

2 moles of KMnO4 * 5 moles of H2O2 = 3 moles of H2O2 * x moles of KMnO4

10 moles of KMnO4 = 3 moles of H2O2 * x moles of KMnO4

Dividing both sides by 3 moles of H2O2:

10 moles of KMnO4 / 3 moles of H2O2 = x moles of KMnO4

So, the number of moles of KMnO4 required to react with 5 moles of H2O2 in acidic medium is approximately 3.33 moles.