Asked by Andy

3Cu+8HNO3--> 3Cu(NO3)2+ 2NO+4H2O

How many moles of HNO3 are required to react with 6 moles of Cu?

How many moles of Cu(NO3)2 are produced when 3 moles of Cu react?

How many moles of Cu must react to produce 4 moles of NO?

If 4 moles of NO are produced, how many moles of H2O are also produced?

How to go about solving these questions? Please help.
Answered by DrBob222
It's all done with the balanced equation and the coefficients. Here is an example. Note how the FACTOR converts from one material to the other.
mols NO = 4. We want to convert to mols Cu.
mols Cu = mols NO x (factor)
factor is 3 mols Cu/2mols NO. So
mols Cu = 4 mols NO x (3 mols Cu/2 mols NO) = 4 x 3/2 = 12/2 = 6
You COULD have written the factor as the reciprocal; i.e., 2 mols NO/3 mols Cu BUT note that the units would not cancel if you did that. So the factor ALWAYS is used so that the unit we don't want cancels and the unit we want the answer to be in is left. Post your answers to the others and someone shall be happy to check them.
Answered by Anonymous
no help my dude
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