A current of 3.78 A is passed through a Pb(NO3)2 solution for 1.40 hours. How much lead is plated out of the solution?

Answer 1

coulombs = amperes x seconds
C = 3.78A x 1.4 hr x (60 min/hr) x (60 s/min) = ?C. Let's estimate it at 19,000 C.
96,485 C will deposit 207.2/2 grams Pb = 96,485 C will deposit 103.6 g Pb.

103.6g Pb x (19,000/96,485) = ?g Pb deposited.