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Asked by aaron

Find two negative numbers such that the sum of their squares is 170 and twice the square of the first minus 3 times the square of the second is 95
12 years ago

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Answered by Steve
a^2+b^2 = 170
2a^2-3b^2 = 95
substituting,
2a^2-3(170-a^2) = 95
5a^2 - 510 = 95
5a^2 = 605
a^2 = 121

a = -11
b = -7
12 years ago
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Find two negative numbers such that the sum of their squares is 170 and twice the square of the first minus 3 times the square of the second is 95

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