Asked by Tangeni.

A spring is extended 4mm by an applied force of 2.0N.
a)What is its spring constant?
b)How much would it extend if a load of 150g was suspended from it?
Answered by Henry
a. K = F/d = 2N/0.004m = 500 N/m.

b. F = m*g = 0.15kg * 9.8N/kg = 1.47 N.
(1.47N/500N) * 1m = 2.94*10^-3 m=2.94 mm
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