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Original Question
the ages of a son and father are in the ratio 3:8. if the son is 35 years younger than his father. find their ages.Asked by riaan
the ages of a son and father are in ratio 3:8. If the son is 35 years younger than his father find their ages.
Answers
Answered by
rbowh
x = father's age
x - 35 = son's age
3/8 = (x - 35)/x
cross multiply
8(x - 35) = 3x
x - 35 = son's age
3/8 = (x - 35)/x
cross multiply
8(x - 35) = 3x
Answered by
p.s.puteho
8x-280=3x
8x-3x=280
5x=280
x=56
8x-3x=280
5x=280
x=56
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