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Tarzan (m = 68kg) swings down from a height of 4.8m on a vine to save Jane (m = 35kg) from some hungry hippos. if he gravs jane in an inelastic collision at the bottom of the vine's path, how high will they swing up to after the collision?
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Answered by
Elena
m₁gh₁ =mv²/2,
v=sqrt(2gh₁)=…
m₁v=(m₁+m₂)u,
u= m₁v/(m₁+m₂)=..
.
(m₁+m₂)u²/2=(m₁+m₂)gh₂,
h₂=(m₁+m₂)u²/2(m₁+m₂)=..
v=sqrt(2gh₁)=…
m₁v=(m₁+m₂)u,
u= m₁v/(m₁+m₂)=..
.
(m₁+m₂)u²/2=(m₁+m₂)gh₂,
h₂=(m₁+m₂)u²/2(m₁+m₂)=..
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