Asked by Kelsey
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 33.0° with the vertical.
(a) What is his speed at the bottom of the swing if he starts from rest?(b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s?
(a) What is his speed at the bottom of the swing if he starts from rest?(b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s?
Answers
Answered by
bobpursley
draw the sketch. How high is he initially?
intialPE=finalKE
b) initialPE+ intialKE= finalKE
intialPE=finalKE
b) initialPE+ intialKE= finalKE
Answered by
Kelsey
I drew the sketch, the problem does not tell me how high he is initially, I can find the equation vfinal = the square root of (2gh) but I don't know what h is.
Answered by
Kathryn
I know this is about 5 years too late, but h would be the length of the vine (21 m)
Answered by
Anonymous
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 24° from the vertical.
What is his speed at the bottom of the swing if he starts from rest?
What is his speed at the bottom of the swing if he starts from rest?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.