Asked by Lawng
During a free kick at a soccer playoff game a 0.7 kg ball at the peak of the kick 14.7 m above the field had a kinetic energy of 39.8 J. How fast was the ball booted by the player on the field?
Answers
Answered by
bobpursley
keinitial+PE initial=kepeak+PEpeak
keinitial+0=39.8+.7*g*14.7
1/2 m v^2=39.8+.7*g*14.7
solve for v
keinitial+0=39.8+.7*g*14.7
1/2 m v^2=39.8+.7*g*14.7
solve for v
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