Question
a soccer player shoots a soccer ball at the opposing goal from 15 m away. If the ball leaves his foot at an angle of 20(degree) with the ground, what must its initial velocity be if it enter the goal 2.0 m above the ground?
Answers
Henry
Range = Vo^2*sin(2A)/g = 15 m.
Vo^2*sin(40)/9.8 = 15
Vo^2*0.0656 = 15
Vo^2 = 228.7
Vo = 15.12 m/s.
Vo^2*sin(40)/9.8 = 15
Vo^2*0.0656 = 15
Vo^2 = 228.7
Vo = 15.12 m/s.