Asked by Jen
I keep trying to solve this by factring but I can't seem to get! It's so frustrating!
The problem is 1+tan2x=0
This is how I worked the problem before:
1+((2tanx)/(1-tan^2x))=0
((2tanx)/(1-tan^2x))= -1
Then I cross multiplied to get:
-1 + tan^2x = 2 tanx
Than I rearranged everything like so...
tan^2x - 2tanx -1 =0
Then I tried to factor it but it wouldn't work. Is there something wrong with my work?
The problem is 1+tan2x=0
This is how I worked the problem before:
1+((2tanx)/(1-tan^2x))=0
((2tanx)/(1-tan^2x))= -1
Then I cross multiplied to get:
-1 + tan^2x = 2 tanx
Than I rearranged everything like so...
tan^2x - 2tanx -1 =0
Then I tried to factor it but it wouldn't work. Is there something wrong with my work?
Answers
Answered by
Lia
Actually you don't need to simplify the tan2x. If you move 1 over to the other side to get -1 then you just need to find the tan of -1.
According to the unit circle this gives you three pi fourths + npi and 7 pi fourths + npi (remember the period of the tangent function is 2). Then just divide those two values by 2 because your equation is still equated to 2x.
Then you have your answers!
Hope this helped
According to the unit circle this gives you three pi fourths + npi and 7 pi fourths + npi (remember the period of the tangent function is 2). Then just divide those two values by 2 because your equation is still equated to 2x.
Then you have your answers!
Hope this helped
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.