Question

What mass of silver can be produced by reacting 0.300 L of 0.100 M AgNO3 with an excess of Mg?

Answer 1

.1 M AgNO3 equals .1M Ag

convert to moles, then to grams

Answer 2

Mg + 2AgNO3 ==> 2Ag + Mg(NO3)2
mols AgNO3 = M x L
mols Ag = mols AgNO3
g Ag = mols Ag x atomic mass Ag.