An initial investment of $12,000 is invested for 2 years in an account that earns 4% interest compounded quarterly. Find the amount of mnoey in the account at the end of the period.

User Icon for Henry Henry answered
11 years ago

P = Po(1+r)^n.

Po = $12,000

r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal.

n = 4Comp./yr. * 2yrs. = 8 Compounding periods.

Plug the above values into the given Eq.
and get $12,994.28.

User Icon for Clown Bot Clown Bot answered
1 year ago

Well, when it comes to money, I'm no mathematician, but I can definitely give it a shot. Let's break it down.

So you have $12,000 invested for 2 years at an interest rate of 4% compounded quarterly.

To calculate the amount of money at the end of the period, we use the formula for compound interest: A = P(1 + r/n)^(nt), where A is the future amount, P is the principal amount, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years.

Plug in the numbers and we get:

A = 12000(1 + 0.04/4)^(4*2)

Now, I'm no fan of doing math, but we can simplify this a bit:

A = 12000(1 + 0.01)^8

And simplify a bit more:

A = 12000(1.01)^8

A = 12000(1.08367839)

A ≈ $12,295.14

So, according to my calculations, at the end of the period, you would have approximately $12,295.14 in the account. Just keep in mind, this is an estimate and doesn't take into account any additional fees or withdrawals.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the amount of money in the account at the end of the period, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the final amount of money
P = the initial investment
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the number of years

Given:
P = $12,000
r = 4% = 0.04 (since it is stated as a decimal)
n = 4 (compounded quarterly)
t = 2 years

Substituting these values into the formula:

A = 12000(1 + 0.04/4)^(4*2)

Simplifying the equation:

A = 12000(1 + 0.01)^8

Calculating inside the parentheses:

A = 12000(1.01)^8

Calculating the exponent:

A = 12000(1.0816)

Calculating the final amount:

A ≈ $12,979.20

Therefore, the amount of money in the account at the end of the period is approximately $12,979.20.

User Icon for Explain Bot Explain Bot answered
1 year ago

To find the amount of money in the account at the end of the period, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:
A = the final amount of money in the account
P = the initial investment (principal)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the number of years the money is invested for

In this case, the initial investment is $12,000, the annual interest rate is 4% (or 0.04 as a decimal), the interest is compounded quarterly (n = 4), and the money is invested for 2 years (t = 2).

Plugging these values into the formula, we get:

A = 12000(1 + 0.04/4)^(4*2)

Let's simplify this step by step:

1 + 0.04/4 = 1.01 (simplifying within the parentheses)

(1.01)^(4*2) = (1.01)^8 (simplifying the exponent)

Using a calculator, we find that (1.01)^8 ≈ 1.0816

Finally, multiplying the result by the initial investment:

A = 12000 * 1.0816

Calculating this multiplication, we find:

A ≈ $12,979.20

Therefore, the amount of money in the account at the end of the period is approximately $12,979.20.