Asked by abdul rahman

A current I=2 Amperes flows in a circular single loop coil of radius R=10 cm.

(a) Evaluate the magnitude of the magnetic field (in Tesla) at a point P on the axis of the coil, and a distance z =5 cm away from the plane of the coil itself.

Now consider two N-turn circular coils of radius R, each perpendicular to the axis of symmetry, with their centers located at z=±l/2 . There is a steady current I flowing in the same direction around each coil, as shown in the figure below.

(b) Assuming the N=100, I=2 Amperes, R=10 cm, l=2 cm calculate the magnitude of the magnetic fied (in Tesla) at a distance z=0.5 cm from the midpoint between the centers of the two coil.

(c) Evaluate the first derivative with respect to z of the magnetic field calculated in part (b) using the same values for the parameters. Express your answer in Tesla per meter.

C) Calculate the second derivative with respect to z of the magnetic field calculated in part (b) using the same values for the parameters. Express your answer in Tesla per meter^2

Answered by FLu
a)0.0000090020201102748
b)0.0025
c) First part -0.00358179

Anyone for second part of part c) Tesla per metre square?
Answered by FLu
Third and Last part of c) is 0 by the way.

second part for c) Tesla per square meter please?
Answered by Mirt
Anyone for second part for c) Tesla per square meter please?
Answered by Trek
Anyone for C) Tesla per square meter please?
Answered by FLu
Abdul Rahman do you have Problem 2 please?
Answered by P
Yes please Problem 2!
Answered by Ruben
URGENT !! PROBLEM 2 !! D:
Answered by FLu
Problem 2 is answered now Ruben, look at my profile. Do you have by any chance Problem 3 c) second part?
tesla in square meter
Answered by Luiis
The second part in c) problem 3 it's tricky ... i didn't got yet. ):
Please angle in the Aurora Zone ??
Answered by FLu
That is easy Luis it is 18.
Please let me know anyone who cracks second answer part c)?

thanks
Answered by Mag
Please answer second part tesla in meters problem 3) c) !
Answered by Luiis
YEAH I GOT IT PROBLEM 3 c) secnd part -0.687332867 !!!
SO PLEASE PROBLEM 4 (b) ??!!!
Hurry up i got 10 minutes to check !!!!!
Answered by FLu
Thanks Luis, it is below!
4)b)
(pi*B^2*L^4*omega)/R
Answered by Luiis
:)Thank youu
Answered by stEvE
what is the answer for 2) a) n 2)b)
Answered by stEvE
answer for that intuition problem???
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