Asked by JASMIN
THE SOLUBILITY PRODUCT CONSTANT FOR BaSO4 AT 298K IS 1.1X10-1O POWER. CALCULATE THE SOLUBILITY OF BaSO4 IN MOL\L AT 298K
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Answered by
Rachael
Basically, when BaSO4 dissolves in water, it dissociates into the ions Ba^+2 and SO4^-2. The solubility product constant expression then becomes as follows:
Ksp=[Ba^+2][SO4^-2]
You already know that the Ksp for BaSO4 is 1.1x10^-10. This means that BaSO4, when it dissociates, has the same concentrstion for its ions.
Ksp=[Ba^+2][SO4^-2]
Ksp=[1.1×10^-10][1.1×10^-10]
Ksp=1.21×10^-20
Ksp=[Ba^+2][SO4^-2]
You already know that the Ksp for BaSO4 is 1.1x10^-10. This means that BaSO4, when it dissociates, has the same concentrstion for its ions.
Ksp=[Ba^+2][SO4^-2]
Ksp=[1.1×10^-10][1.1×10^-10]
Ksp=1.21×10^-20
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