Asked by Jack
If the solubility constant for Ag2CO3 is equal to 8.1x10^-12 how many grams of Ag2CO3 will dissolve in a .0001 M solution of Na2CO3?
Answers
Answered by
DrBob222
.....Ag2CO3 ==< 2Ag^+ + CO3^2-
I.....solid......0.....0.0001
C.....solid......2x.......x
E.....solid......2x...0.0001+x
Subsitute the E line into the Ksp epxression and solve for x = solubility in M. Then grams = mols x molar mass
I.....solid......0.....0.0001
C.....solid......2x.......x
E.....solid......2x...0.0001+x
Subsitute the E line into the Ksp epxression and solve for x = solubility in M. Then grams = mols x molar mass
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