Asked by Janice
When 1.00 g. of MgCO3 is added to 2.0 L of water, some, but not all, will dissolve to form a saturated solution. Calculate the mass of solid that remains undissolved.
Answers
Answered by
DrBob222
........MgCO3 ==> Mg^2+ + CO3^2-
I.......solid.....0........0
C...x dissolves...x........x
E.......solid......x.......x
Ksp = (Mg^2+)(CO3^2-)
Substitute for Ksp and the E line from the ICE chart and solve for x = solubility MgCO3 in mols/L.
You have 2L therefore, the solubility will be ?mols/L x 2L = ? then convert that to grams by g = mols x molar mass.
Subtract from 1.00g to find the amount not dissolved.
I.......solid.....0........0
C...x dissolves...x........x
E.......solid......x.......x
Ksp = (Mg^2+)(CO3^2-)
Substitute for Ksp and the E line from the ICE chart and solve for x = solubility MgCO3 in mols/L.
You have 2L therefore, the solubility will be ?mols/L x 2L = ? then convert that to grams by g = mols x molar mass.
Subtract from 1.00g to find the amount not dissolved.
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