Asked by c
Given a 10.0g sample of MgCO3*5H2O, what weight of anhydrous magnesium carbonate can be obtained after driving off the water?
The GFM of the sample is 174.3amu. Now.. how do I go about finding the weight of the magnesium carbonate?
The GFM of the sample is 174.3amu. Now.. how do I go about finding the weight of the magnesium carbonate?
Answers
Answered by
manisha
magnesium carbonate consist of one atom of Mg,one atom of c,three atoms of O.SO weight of magnesium carbonate is
24 + 12 + (3*16)
=24 +12+ 48
=84
24 + 12 + (3*16)
=24 +12+ 48
=84
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