magnesium carbonate consist of one atom of Mg,one atom of c,three atoms of O.SO weight of magnesium carbonate is
24 + 12 + (3*16)
=24 +12+ 48
=84
Given a 10.0g sample of MgCO3*5H2O, what weight of anhydrous magnesium carbonate can be obtained after driving off the water?
The GFM of the sample is 174.3amu. Now.. how do I go about finding the weight of the magnesium carbonate?
1 answer
3 answers