Asked by dave
Calculate the number of coulombs of positive charge in 261 cm3 of (neutral) water. (Hint: A hydrogen atom contains one proton; an oxygen atom contains eight protons.)
Answers
Answered by
drwls
261 cm^3 has a mass of 260 g and that is 260/18 = 14.44 moles of H2O. Each mole has 6.02*10^23 molecules, and each molecule has 10 protons.
14.44 x 6.02*10^23 x 10 = __?__ protons
Multiply that by e = 1.60*10^-19 Coulombs per proton for the number of coulombs
14.44 x 6.02*10^23 x 10 = __?__ protons
Multiply that by e = 1.60*10^-19 Coulombs per proton for the number of coulombs
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