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A bag contains 150 balls numbered 1 through 150. Three balls are drawn and placed on the table. The probability that the balls were drawn in increasing order can be expressed as a/b where a and b are coprime positive integers. What is the value of a+b?
Answers
Answered by
Reiny
number of ways to draw 3 balls from 150
= 150x149x148 = 3307800
But these include triplets of the form
ABC
ACB
BAC
BCA
CAB
CBA , that is , containing the same three numbers.
Only one of these 6 would have them in the correct increasing order ,so we divide 3307800 by 6 to get 551300
so the prob of your event = 551300/3307800
= 1/6
so a/b = 1/6, and a+b = 7
= 150x149x148 = 3307800
But these include triplets of the form
ABC
ACB
BAC
BCA
CAB
CBA , that is , containing the same three numbers.
Only one of these 6 would have them in the correct increasing order ,so we divide 3307800 by 6 to get 551300
so the prob of your event = 551300/3307800
= 1/6
so a/b = 1/6, and a+b = 7
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