yes, OR=Pa + Pb
Peven=5/10 Prob5=1/10
pr OR= 6/10 or 3/5
A lottery game has balls numbered from 0 - 9
If a ball is selected at random, what is the probability of selecting an even numbered ball or a 5 ?
I am guessing this is Mutually exclusive event and hence used the OR= P(A)+P(B) concept
considering 0 as an even number I keep getting 1 as an answer..
help me out.. am I doing it wrong?
2 answers
Of course how silly of me to put 5/10 for probability of 5 -_-
1 answer