Asked by Lucie
For a lottery game, each ticket has a probability of 1 / 3.09 = 0.324 of winning a prize. Every friday you buy 1 lottery game.
a) What is the probability you will win on two of your next three games?
a) What is the probability you will win on two of your next three games?
Answers
Answered by
Damon
p = p win = .324
1-p = p lose = .676
binary distribution
P(x = k) = C(n,k) p^k (1-p)^(n-k)
C(2,3) = 3!/2!(3-2)! = 3
so
= 3(.324)^2 (.676)
= .213
1-p = p lose = .676
binary distribution
P(x = k) = C(n,k) p^k (1-p)^(n-k)
C(2,3) = 3!/2!(3-2)! = 3
so
= 3(.324)^2 (.676)
= .213
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