1.
prob(a 3) = 1/6
prob(greater than 3) = 3/6 = 1/2
since you want prob a red 3 AND
you would have
(1/6)*(1/2) = 1/12
How did you get 3/5 ?
2.
prob(first greater than 25) = 26/50
prob(second greater than 25) 25/49
prob (third greater than 25) = 24/48
so ...
26/50 * 25/49 * 24/48 = 13/98
1) A red die and a blue die are tossed. What is the probability that the red die shows a 3 and the blue die shows a number greater than 3?
Answer: 3/5
2) Tickets are numbered 1 to 50 and placed in a box. Three tickets are drawn at random without replacement. What is the probability that their numbers are all greater than 25?
Answer: 23/196
Are these answers correct?
Thanks for your help.
1 answer
1 answer