Question

If the specific heat of water = 4190 J/kg /°C and a total of 120g of hot water at 95°C is poured into the calorimeter, resulting in a final equilibrium temperature of 73°C, how many joules of heat are lost by the water? 11061.6

If the specific heat of copper = 390 J/kg /°C and the mass of the copper calorimeter is 70 g , how many joules of heat are gained by the calorimeter as its temperature changes from 22°C to the equilibrium temperature of 73°C? 11392.3

Need help with this part -
If the water had lost 12000 joules and the calorimeter gained 1300 joules as the temperature of both rock and calorimeter increased from 22°C to 73°C and the mass of rock in the calorimeter was 185 grams, what is the specific heat, c, of the rock material?
(CALCULATE YOUR ANSWER IN SI UNITS, but do not state the units in the answer).
Answer

Answer 1

Heat lost by water equals
(Heat gained by calorimeter)
PLUS
(Heat gained by rock)

12,000 = 1300 + Mrock*Crock*(delta T)

10,700= 0.185*Crock*51

Solve for Crock in J/kg*C

Answer 2

thank you