the specific heat of water is 4.184 j/g °c. How many grams of water at 85 C would have to be added to raise 1.00 kg of water from 25.0 C to 50.0 C?

Question

Please help I am not sure of where to start!

Answer 1

The sum of the heats gained has to be zero.

heataddedwater+heatstartingwater=0
massadded*c(50-85)+1kg*cw*(50-25)=0
solve for massadded.

Answer 2

why did you take 50-85??

Answer 3

(Tfinal-tempInitial)

Answer 4

So I got 714 grams of water but it doesnt seem right to me some how.

Answer 5

sounds ok to me, you are heating 1000 grams by 25 degrees, cooling 714 by 35 degrees... about equal

Answer 6

But looking at the question if you add 714 grams of water at temp 85C would 1000 g of water will raise from 25C to 50C. I feel like if you add that much water of 85C the water temp will be a lot more higher than 50 C

Answer 7

do the math:
heat lost=714*c*35=
heat gained=1000c*25=

are they equal?

Answer 8

Yes.
I think I get it now.
Thank you for your help!