Asked by Anonymous

the specific heat of water is 4.184 j/g °c. How many grams of water at 85 C would have to be added to raise 1.00 kg of water from 25.0 C to 50.0 C?
Please help I am not sure of where to start!
Answered by bobpursley
The sum of the heats gained has to be zero.

heataddedwater+heatstartingwater=0
massadded*c(50-85)+1kg*cw*(50-25)=0
solve for massadded.
Answered by Anonymous
why did you take 50-85??
Answered by bobpursley
(Tfinal-tempInitial)
Answered by Anonymous
So I got 714 grams of water but it doesnt seem right to me some how.
Answered by bobpursley
sounds ok to me, you are heating 1000 grams by 25 degrees, cooling 714 by 35 degrees... about equal
Answered by Anonymous
But looking at the question if you add 714 grams of water at temp 85C would 1000 g of water will raise from 25C to 50C. I feel like if you add that much water of 85C the water temp will be a lot more higher than 50 C
Answered by bobpursley
do the math:
heat lost=714*c*35=
heat gained=1000c*25=

are they equal?
Answered by Anonymous
Yes.
I think I get it now.
Thank you for your help!