Asked by Anonymous
When a charged particle moves at an angle of 12° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.8F?
Answers
Answered by
Elena
F=qvB sin12⁰
1.8F=qvBsinφ
sinφ/sin12⁰ =1.8
sinφ =sin12⁰•1.8=0.208•1.8=0.374
φ=sin⁻¹0.374=22⁰
1.8F=qvBsinφ
sinφ/sin12⁰ =1.8
sinφ =sin12⁰•1.8=0.208•1.8=0.374
φ=sin⁻¹0.374=22⁰
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