A 2.53-μC charged particle with a kinetic energy of 0.0929 J is fired into a uniform magnetic field of magnitude 0.147 T. If the particle moves in a circular path of radius 2.92 m, determine its mass.

Answer 1

centripetal force=magnetic force
mv^2/r=qvB
1/2 mv^2=rqvB/2
solve for v, you are given KE 1/2 mv^2, r, q, B

now knowing v, solve for mass
mass=2*KE/v