Asked by Shadow
The temperature of oxygen is 810 torr at 298 K , what will the pressure be at 330 K?
Using Lussac's Law, would the answer be 896.98 torr? Thanks
Using Lussac's Law, would the answer be 896.98 torr? Thanks
Answers
Answered by
bobpursley
constant volume
P1=P2*T1/T2
=810*330/298=yes
P1=P2*T1/T2
=810*330/298=yes
Answered by
Shadow
For Boyle, Lussac, and Charles Law, do I have to convert the units to the standard measurement? Like temperature to kelvin and pressure to atm? Thanks
Answered by
bobpursley
Temperature must be in kelvins. The others do not have to be changed.
Answered by
Shadow
Bob, could you verify this answer for me too please? Thanks
P1 = 1.08 atm
V1 = 250 mL
T1 = 297 K
T2 = 310.2 K
P2 = 2.25 atm
Would V2 = 125.3 mL?
P1 = 1.08 atm
V1 = 250 mL
T1 = 297 K
T2 = 310.2 K
P2 = 2.25 atm
Would V2 = 125.3 mL?
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