Question
Calculate the standard free-energy change for the following reaction at 25 C degrees.
2Au^3+(aq)+3Ni(s) <-- --> 2Au(s)+3Ni^2+(aq)
Ni2+(aq) + 2e¨C ¡ú Ni(s) E=¨C0.26
Au3+(aq) + 3e¨C ¡ú Au(s) E=+1.498
G= ? KJ
Would it be G=1.758?
2Au^3+(aq)+3Ni(s) <-- --> 2Au(s)+3Ni^2+(aq)
Ni2+(aq) + 2e¨C ¡ú Ni(s) E=¨C0.26
Au3+(aq) + 3e¨C ¡ú Au(s) E=+1.498
G= ? KJ
Would it be G=1.758?
Answers
DrBob222
My calculator went out so I can't calculate this. My table gives Ni^2+ ==>Ni as -0.26
So Ecell = 1.498 + 0.26 = ?
dG = -nFE = 6*96,485*Ecell
So Ecell = 1.498 + 0.26 = ?
dG = -nFE = 6*96,485*Ecell
Anon
I got -1.02*10^6 but it is wrong.
DrBob222
Well, I copied your number instead of what I thought it was so Ecell = 1.49 + (-0.26) = ?
I did this on google and obtained an answer of 717 kJ but you need to go through and clean it up. Especially the number of significant figures. These databases are unforgiving.
I did this on google and obtained an answer of 717 kJ but you need to go through and clean it up. Especially the number of significant figures. These databases are unforgiving.
Anon
It is still wrong.