Asked by Katie
Calculate the molar mass of a diprotic acid.
It reaches the endpoint of the titration with NaOH at 28ml.
The initial concentration of NaOH is 0.09792. and the initial mass of the diprotic acid is 0.685g. I keep getting a molar mass of 500g/mol. but the options are all around 100-150.
It reaches the endpoint of the titration with NaOH at 28ml.
The initial concentration of NaOH is 0.09792. and the initial mass of the diprotic acid is 0.685g. I keep getting a molar mass of 500g/mol. but the options are all around 100-150.
Answers
Answered by
bobpursley
molesbase=1/2 moles acid
.028*.09792*1/2 .685/molmass
molmassacid= .685/(2* .028*.097920
I don't get anything near 500g/mol
.028*.09792*1/2 .685/molmass
molmassacid= .685/(2* .028*.097920
I don't get anything near 500g/mol
Answered by
Katie
So you need to times the molarity by two?
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