Question

prove that : 3^-3 * 6^2 * root 98 / 5^2 * cube root 1/25 * 15^-4/3 *3^1/3 is equal to 28 root 2

Answer 1

3^-3 * 6^2 * root 98 / 5^2 * cube root 1/25 * 15^-4/3 *3^1/3
= (1/27)*(36)*(7√2)/25 * (1/25)^(1/3) * (1/3)^(4/3) * (1/5)^(4/3) * 3(1/3)
= (3/4) * 7√2/25) * (1/5)^(2/3) * (1/5)^(4/3) * (1/3)^(4/3) * 3^(1/3)
= (3/4)(7√2/25) * .......

not working out at all

perhaps there should have been some brackets.
e.g. was it (√98)/25 as you typed it, or
was it √(98/25) ?

Answer 2

=1/3^3×3^2×4×7√2/5^2×(1/25)^1/3×1/3^4/3×1/5^4/3×3^1/3
=3^2×28√2×5^1/3×5^1/3×3^4/3×5^4/3/3^3×5^2×3^1/3
=28√2×3^2+4/3×5^1/3+1/3+4/3/3^3+1/3×5^2
=28√2×3^10/3×5^2/3^10/3×5^2
=28√2

Answer 3

Great job
😊nicely done