Asked by Jeconiah

log(x-2) +log8 (x-4) =log6 (x-1)
Answered by Steve
log(x-2) + log(x-4)/log8 = log(x-1)/log6
log[(x-2)(x-4)^(1/log8)] = log[(x-1)^(1/log6)]

(x-2)(x-4)^(1/log8) = (x-1)^(1/log6)
Ya got me.

Something tells me the problem was not as posted.
Answered by Cedric
please solve it
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