Question
log(x-2) +log8 (x-4) =log6 (x-1)
Answers
Steve
log(x-2) + log(x-4)/log8 = log(x-1)/log6
log[(x-2)(x-4)^(1/log8)] = log[(x-1)^(1/log6)]
(x-2)(x-4)^(1/log8) = (x-1)^(1/log6)
Ya got me.
Something tells me the problem was not as posted.
log[(x-2)(x-4)^(1/log8)] = log[(x-1)^(1/log6)]
(x-2)(x-4)^(1/log8) = (x-1)^(1/log6)
Ya got me.
Something tells me the problem was not as posted.
Cedric
please solve it