Asked by lt
How do I solve:
log6 (x^2-5x) = 1
1/2log5(r-2)-log5 r)
log2 (x-1/x^8)
I really don't know how to do these or even start
log6 (x^2-5x) = 1
1/2log5(r-2)-log5 r)
log2 (x-1/x^8)
I really don't know how to do these or even start
Answers
Answered by
drwls
I assume the number immediately after log is the base of the log.
log6 (x^2-5x) = 1 is equivalent to writing
6^1 = x^2-5x = 6
Rewrite as a polynomial
x^2 -5x -6 = 0
(x-6)(x+1) = 0
x = 6 or -1
Do the others the same way. Rewrite the equation containing the log term as a polynomial, and factor it.
log6 (x^2-5x) = 1 is equivalent to writing
6^1 = x^2-5x = 6
Rewrite as a polynomial
x^2 -5x -6 = 0
(x-6)(x+1) = 0
x = 6 or -1
Do the others the same way. Rewrite the equation containing the log term as a polynomial, and factor it.
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