Asked by Steven
If \cot \left(\sin^{-1} \frac{1}{5}\right) = m, what is the value of m^2?
Answers
Answered by
Steve
cot(arcsin(1/5))
draw a triangle. If sin=1/5, cot=√24
m^2=24
draw a triangle. If sin=1/5, cot=√24
m^2=24
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