Question
A 30.3-kg child starting from rest slides down a water slide with a vertical height of 10.5 m. (Neglect friction.)
(a) What is the child's speed halfway down the slide's vertical distance?
(a) What is the child's speed halfway down the slide's vertical distance?
Answers
V^2 = Vo^2 + 2g*d
V^2 = 0 + 19.8*(10.5-5.25)
V^2 = 1102.9
V = 10.1 m/s.
V^2 = 0 + 19.8*(10.5-5.25)
V^2 = 1102.9
V = 10.1 m/s.
Correction: V^2 = 102.9.
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