Asked by mary
A 35.9 kg child starting from rest slides down a water slide with a vertical height of 20.3 m. (Neglect friction.)What is the child speed half way down
Answers
Answered by
Steve
PE at top: mgh = 35.9*9.8*20.3 = 7142 J
She loses half that on the way down.
KE = 1/2 mv^2 = 3571
So, v^2 = 3571/35.9 = 99.47
Call it 100
So, v = 10
She loses half that on the way down.
KE = 1/2 mv^2 = 3571
So, v^2 = 3571/35.9 = 99.47
Call it 100
So, v = 10
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