Asked by Jenn
Solve the inequality x^2(8+x)(x-9)/(x+4)(x-7) is greater than or equal to 0?
Answers
Answered by
black_widow
x^2(8+x)(x-9)/(x+4)(x-7) >=0
x^2(8+x)(x-9)(x+4)(x-7)>=0
therefore the ranges are x>=9,0<=x<=7,-8<=x<=-4
But x cannot equal -4 or 7
therefore the ranges of x are
x>=9,0<=x<7,-8<=x<-4
x^2(8+x)(x-9)(x+4)(x-7)>=0
therefore the ranges are x>=9,0<=x<=7,-8<=x<=-4
But x cannot equal -4 or 7
therefore the ranges of x are
x>=9,0<=x<7,-8<=x<-4
Answered by
Steve
Hmm. I get
x in (-oo,-8] U [-4,7] U (9,+oo)
Gotta watch to be sure top and bottom are same sign.
x in (-oo,-8] U [-4,7] U (9,+oo)
Gotta watch to be sure top and bottom are same sign.
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