How much heat, in joules and calories, is needed to heat up 295 mL of water from 26.6 °C to 85.1 °C? Assume the density of water to be 1.00 g/mL.

1 answer

heat=mass*specificheat*changintemp
= 295ml*1g/ml*1cal/gram*(85.1-26.6)

that give it to you in calories.

change the units of specific heat if you want it in joules.