Asked by dug
How much heat, in joules and calories, is needed to heat up 295 mL of water from 26.6 °C to 85.1 °C? Assume the density of water to be 1.00 g/mL.
Answers
Answered by
bobpursley
heat=mass*specificheat*changintemp
= 295ml*1g/ml*1cal/gram*(85.1-26.6)
that give it to you in calories.
change the units of specific heat if you want it in joules.
= 295ml*1g/ml*1cal/gram*(85.1-26.6)
that give it to you in calories.
change the units of specific heat if you want it in joules.
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