Asked by dug

How much heat, in joules and calories, is needed to heat up 295 mL of water from 26.6 °C to 85.1 °C? Assume the density of water to be 1.00 g/mL.

Answers

Answered by bobpursley
heat=mass*specificheat*changintemp
= 295ml*1g/ml*1cal/gram*(85.1-26.6)

that give it to you in calories.

change the units of specific heat if you want it in joules.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions