Asked by Tammy
How many joules of heat are removed to completely covert 70.0 grams of water to ice at zero Celcius?
Answers
Answered by
Olereb48
q = 80cal/gm x 70gms = 5600cals x 4.184J/cal = 23,430 joules ~ 23,000 joules with 2 sig gigs.
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