Question

how many grams of Ag2CO3 will precipitate when excess Na2CO3 solution is added to 64.0 mL of 0.554 M AgNO3 solution?

Answer 1

2AgNO3 + Na2CO3 ==> Ag2CO3 + 2NaNO3
mols AgNO3 = M x L = ?
Convert mols AgNO3 to mols Ag2CO3.
g Ag2CO3 = mols Ag2CO3 x molar mass.