Asked by Anonymous
the Ksp of Ag2CO3 is 8.1x10-12. what is the molar solubility of silver carbonate?
can you please walk me through this?
can you please walk me through this?
Answers
Answered by
DrBob222
Ag2CO3 ==> 2Ag^+ + CO3^-2
Ksp = (Ag^+)^2(CO3^-2)
Set up and ICE chart, substitute into the Ksp expression, and solve. Post your work if you get stuck.
Ksp = (Ag^+)^2(CO3^-2)
Set up and ICE chart, substitute into the Ksp expression, and solve. Post your work if you get stuck.
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